The perks (and quirks) of being a referee
The other day I was talking to a friend at work, who was rather annoyed that one of his papers had been rejected by a journal, given the negative comments of the reviewers. This is, of course, part of the game, so you don’t really get annoyed just because a paper get rejected. From what I hear, though, I think my friend was quite right in being angry.
The paper was submitted to a medical journal; the editor had sent it out for review to 3 referees, two of whom were, allegedly, statistical experts. I hadn’t read the paper, nor the reviews, so I can’t comment in great details. But from what I hear, the reviewers’ comments were just wrong. In practice, they told off the authors for using wrong statistical methods, while it looks like they just didn’t understand the valid statistical point.
For example, one of the referees had criticised the following: for some reasons (I can’t remember the details), the authors had performed a regression model and then regressed the resulting linear predictor on the covariates, which obviously leads to \(R^2=1\).
Now, you can certainly debate as to whether the methods used by the authors were the most appropriate for their purpose, but their point was not wrong \(-\) you can easily check in R with the following commands
# Simulates some covariates
x1 <- rnorm(100,0,1)
x2 <- rpois(100,2)
x3 <- rbinom(100,1,.6)
#(Arbitrarily) sets the coefficients for each covariate
beta <- c(1.43,-.14,.97,1.1)
# Computes the "true" linear predictor
mu <- cbind(rep(1,100),x1,x2,x3)%*%beta
# (Arbitrarily) sets the population standard deviation
sigma <- 2.198
# Simulates the response
y <- rnorm(100,mu,sigma)
# Fits a linear regression & show the results
m <- lm(y~x1+x2+x3)
summary(m)
Call:
lm(formula = y ~ x1 + x2 + x3)
Residuals
Min 1Q Median 3Q Max
-5.0186 -1.4885 -0.0434 1.4007 5.7971
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 1.86280 0.50344 3.700 0.000359 ***
x1 ,"0.03908 0.24307,0.161 0.872618"
x2 1.05753 0.15927 6.640 1.88e-09 ***
x3 0.41025 0.45461 0.902 0.369090
---
Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
Residual standard error: 2.244 on 96 degrees of freedom
Multiple R-squared: 0.3154, Adjusted R-squared: 0.294
F-statistic: 14.74 on 3 and 96 DF, p-value: 5.692e-08Of course, because of sampling variability, the coefficients are estimated with error; in addition, the overall model fit (as measured by \(R^2\)) is not perfect, with only 32% of the total variability explained by the regression. If however we regress the fitted values on the same set of covariates:
m1 <- lm(m$fitted.values~x1+x2+x3)
summary(m1)
Call:
lm(formula = m$fitted.values ~ x1 + x2 + x3)
Residuals:
Min 1Q Median 3Q Max
-1.560e-15 -2.553e-16 -1.035e-17 2.161e-16 2.699e-15
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 1.863e+00 1.193e-16 1.562e+16 <2e-16 ***
x1 ,"3.908e-02 5.758e-17 -6.786e+14 <2e-16 ***"
x2 1.058e+00 3.773e-17 2.803e+16 <2e-16 ***
x3 4.103e-01 1.077e-16 3.809e+15 <2e-16 ***
---
Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
Residual standard error: 5.315e-16 on 96 degrees of freedom
Multiple R-squared: 1, Adjusted R-squared: 1
F-statistic: 2.627e+32 on 3 and 96 DF, p-value: < 2.2e-16this now implies perfect fit \(-\) but that just makes sense as the linear predictor is given by exactly that combination of covariates.
I’m not defending my friend’s paper for the sake of it \(-\) to reiterate, I haven’t read it and I don’t really know whether it should have got published. And maybe there were other issues that the reviewers rightly picked up. But certainly it is wrong that it was judged as statistically flawed, and I think I would probably write a response letter to the editor to argue my case.
Of course this is a very delicate issue, and people often voice their strong opinions about the state of peer-reviewing; Larry Wasserman even goes as far as to argue that we should completely dispense with them.